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NEET Sample Paper NEET Sample Test Paper-87

  • question_answer
    0.4 moles of HCl and 0.2 moles of \[CaC{{l}_{2}}\] were dissolved in water to have 500 mL of solution, the molarity of \[C{{l}^{-}}\]ion is:

    A) 0.8 M   

    B)        1.6 M

    C) 1.2 M               

    D) 10.0M

    Correct Answer: B

    Solution :

    [b] \[\underset{0.4\,\,moles}{\mathop{HCl}}\,{{H}^{+}}+\underset{0.4\,\,moles}{\mathop{C{{l}^{-}}}}\,\] \[\underset{0.2\,\,moles}{\mathop{CaC{{l}_{2}}}}\,C{{a}^{2+}}+\underset{2\times 0.2=0.4\,\,moles}{\mathop{2C{{l}^{-}}}}\,\] Total \[C{{l}^{-}}moles=0.4+0.4=0.8\,moles\] \[Molarity=\frac{Moles}{Vol.in\,\,L}\] \[\therefore \] Molarity of \[C{{l}^{-}}=\frac{0.8}{0.5}=1.6\,\,M.\]


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