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NEET Sample Paper NEET Sample Test Paper-87

  • question_answer
    s The heats of neutralisation of \[C{{H}_{3}}COOH,\] \[HCOOH,\] \[HCN\] and \[{{H}_{2}}S\] are \[-13.2,\] \[-13.4,\] \[-2.9\] and \[-3.8\] kcal per equivalent respectively. Arrange the acids in increasing order of strength

    A) \[HCOOH>C{{H}_{3}}COOH>{{H}_{2}}S>HCN\]

    B) \[C{{H}_{3}}COOH>HCOOH>{{H}_{2}}S>HCN\]

    C) \[{{H}_{2}}S>HCOOH>C{{H}_{3}}COOH>HCN\]

    D) \[HCOOH>{{H}_{2}}S>C{{H}_{3}}COOH>HCN\]

    Correct Answer: A

    Solution :

    [a] The greater the (negative value) of heat of neutralisation, the more is the strength of the acid. Hence, \[HCOOH>C{{H}_{3}}COOH>{{H}_{2}}S>HCN\]


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