A) 0.25 mole
B) 0.50 mole
C) 0.333 mole
D) 0.125 mole
Correct Answer: D
Solution :
[d] \[\underset{\underset{1\,\,\,moles}{\mathop{2\,\,moles}}\,}{\mathop{2{{H}_{3}}As{{O}_{4}}}}\,+5{{H}_{2}}S\xrightarrow{Conc.HCl}\underset{\underset{1/2\,\,moles}{\mathop{1\,\,moles}}\,}{\mathop{A{{s}_{2}}{{S}_{5}}}}\,+8{{H}_{2}}O\] \[\therefore \] number of moles of \[{{H}_{3}}As{{O}_{4}}\] \[=\frac{35.5}{142}=0.25.\] \[\therefore \]number of moles of \[A{{s}_{2}}{{S}_{5}}\] \[=\frac{0.25}{2}=0.125\,mole.\]
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