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NEET Sample Paper NEET Sample Test Paper-87

  • question_answer
    The current in a coil of L = 40 mH is to be increased uniformly from 1A to 11 A in 4 milli sec. The induced e.m.f. will be

    A) 100 V   

    B)        0.4 V

    C) 440 V   

    D)        40 V

    Correct Answer: A

    Solution :

    [a] \[e=\frac{LdI}{dt}=\frac{40\times {{10}^{-3}}(11-1)}{4\times {{10}^{-3}}}=100\,V\]


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