A) \[\frac{{{E}_{n}}}{2}\]
B) \[2{{E}_{n}}\]
C) \[4{{E}_{n}}\]
D) \[\frac{{{E}_{n}}}{4}\]
Correct Answer: C
Solution :
[c] For nth orbit, energy, \[{{E}_{n}}=\frac{2{{\pi }^{2}}e{{m}^{4}}{{z}^{2}}}{{{n}^{2}}{{h}^{2}}}\] For hydrogen (z = 1), \[{{E}_{n}}=\frac{2{{\pi }^{2}}e{{m}^{4}}}{{{n}^{2}}{{h}^{2}}}\] For helium (z = 2), So, \[E=\frac{2{{\pi }^{2}}e{{m}^{4}}\times 4}{{{n}^{2}}{{h}^{2}}}\] \[\frac{E}{{{E}_{n}}}=\frac{4}{1}\]\[\Rightarrow \]\[E=4{{E}_{n}}\]
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