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NEET Sample Paper NEET Sample Test Paper-87

  • question_answer
    A man measures the period of a simple pendulum inside a stationary lift and finds it to be T s. If the lift accelerates upwards with an acceleration g / 4, then the period of the pendulum will be

    A) \[T\]                 

    B)        \[\frac{T}{4}\]  

    C) \[\frac{2T}{\sqrt{5}}\]   

    D) \[2T\sqrt{5}\]

    Correct Answer: C

    Solution :

    [c] \[T=2\pi \sqrt{\frac{\ell }{g}},\] \[T'=2\pi \sqrt{\frac{\ell }{g+a}}=2\pi \sqrt{\frac{\ell }{g+\frac{g}{4}}}=\frac{2}{\sqrt{5}}T.\]                


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