NEET Sample Paper NEET Sample Test Paper-87

  • question_answer
    A dip circle is so set that its needle moves freely in the magnetic meridian. In this position, the angle of dip is \[40{}^\circ .\] Now the dip circle is rotated so that the plane in which the needle moves makes an angle of \[30{}^\circ \] with the magnetic meridian. In this position, the needle will dip by an angle

    A) \[40{}^\circ \]              

    B)        \[30{}^\circ \]

    C) more than \[40{}^\circ \]

    D)        less than \[40{}^\circ \]

    Correct Answer: D

    Solution :

    [d] \[{{\delta }_{1}}=40{}^\circ ,\]\[{{\delta }_{2}}=30{}^\circ ,\]\[\delta =?\] \[\cot \delta =\sqrt{{{\cot }^{2}}{{\delta }_{1}}+{{\cot }^{2}}{{\delta }_{2}}}\] \[=\sqrt{{{\cot }^{2}}40{}^\circ +{{\cot }^{2}}30{}^\circ }\] \[\cot \delta =\sqrt{{{1.19}^{2}}+3=}2.1\] \[\therefore \]\[\delta =25{}^\circ \]  i.e. \[\delta <40{}^\circ .\]


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