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NEET Sample Paper NEET Sample Test Paper-87

  • question_answer
    The mass number of He is 4 and that for sulphur is 32. The radius of sulphur nuclei is larger than that of helium by

    A) \[\sqrt{8}\]                                

    B) \[4\] 

    C) \[2\]                 

    D)        \[8\]

    Correct Answer: C

    Solution :

    [c] \[\frac{{{R}_{s}}}{{{R}_{\alpha }}}={{\left( \frac{{{A}_{s}}}{{{A}_{\alpha }}} \right)}^{1/3}}={{\left( \frac{32}{4} \right)}^{1/3}}=2\]


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