A) \[2.1\times {{10}^{-3}}{{s}^{-1}}\]
B) \[2.1\times {{10}^{-4}}{{s}^{-1}}\]
C) \[2.1\times {{10}^{-5}}{{s}^{-1}}\]
D) \[2.1\times {{10}^{-6}}{{s}^{-1}}\]
Correct Answer: D
Solution :
[d] For nuclear disintegration \[\lambda =\frac{2.303}{t}\log \frac{{{N}_{0}}}{{{N}_{0}}-N}\] \[=\frac{2.303}{24\times 60\times 60}\log \frac{100}{82}=2.1\times {{10}^{-6}}{{\sec }^{-1}}\]
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