A) \[50\,mL\,\,\text{of}\,\,0.1\,MHCl+50\,mL\,\,\text{of}\,\,0.1\,M\,NaCl\]
B) \[50\,mL\,\text{of}\,\,0.1\,M{{H}_{2}}S{{O}_{4}}+50\,mL\,\text{of}\,0.2\,M\,NaOH\]
C) \[50\,mL\,\text{of}\,\,0.1\,MC{{H}_{3}}COOH+50\,mL\,\text{of}\,0.1\,M\,KOH\]
D) \[50\,mL\,\text{of}\,\,0.1\,MHN{{O}_{3}}+50\,mL\,\text{of}\,\,0.1\,M\,N{{H}_{3}}\]
Correct Answer: C
Solution :
[c] \[[{{H}^{3}}{{O}^{+}}]=\frac{0.1}{2}=0.05;\] \[pH=-\log 0.05=1.301\] [b] Complete neutralization of strong acid and strong base,\[pH=7.\] [c] Hydrolysis of the salt \[C{{H}_{3}}COOK,\] \[pH>7\] (salt of weak acid with strong base) [d] Hydrolysis of the salt \[N{{H}^{4}}N{{O}_{3}},\] \[pH<7\](salt of strong acid with weak base)
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