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NEET Sample Paper NEET Sample Test Paper-86

  • question_answer
    \[N{{H}_{4}}Cl\] crystallises in a bcc lattice with edge length of unit cell equal to 387 pm. If the radius of the \[C{{l}^{-}}\] ion is 181 pm, the radius of \[\overset{+}{\mathop{N}}\,{{H}_{4}}\] ions is

    A) 366.3 pm                      

    B) 154.1 pm

    C) 92.6 pm           

    D) None of these

    Correct Answer: B

    Solution :

    [b] For bcc lattice \[2{{r}^{+}}\,\,+2\overline{r}=a\sqrt{3}\] \[\therefore \] \[{{r}_{NH_{4}^{+}}}+{{r}_{C{{l}^{-}}}}=\frac{a\sqrt{3}}{2}=\frac{387\times 1.732}{2}=335.1\] or, \[{{r}_{C{{l}^{-}}}}=335.1-101.0=154.1\,pm\]


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