A) \[P{{b}_{3}}{{O}_{4}}\]
B) \[PbO\]
C) \[2PbC{{O}_{3}}.Pb{{(OH)}_{2}}\]
D) \[Pb{{(C{{H}_{3}}COO)}_{2}}.Pb{{(OH)}_{2}}\]
Correct Answer: C
Solution :
[c] White lead is \[2PbC{{O}_{3}}.Pb{{(OH)}_{2}}\] which is prepared by \[Pb{{(N{{O}_{3}})}_{2}}\] & \[N{{a}_{2}}C{{O}_{3}}.\] It is called as basic lead carbonate. \[3Pb{{(N{{O}_{3}})}_{2}}+3N{{a}_{2}}C{{O}_{3}}+{{H}_{2}}O\xrightarrow{{}}\] \[Pb{{(OH)}_{2}}+\underset{\text{Basic}\,\,\text{lead}\,\,\text{carbonate}}{\mathop{2PbC{{O}_{3}}+NaN{{O}_{3}}}}\,+C{{O}_{2}}\]
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