A) \[HClO>HCl{{O}_{2}}>HCl{{O}_{3}}>HCl{{O}_{4}}\]
B) \[HCl{{O}_{2}}>HCl{{O}_{3}}>HClO>HCl{{O}_{4}}\]
C) \[HCl{{O}_{4}}>HCl{{O}_{3}}>HCl{{O}_{2}}>HClO\]
D) \[HCl{{O}_{3}}>HCl{{O}_{4}}>HClO>HCl{{O}_{2}}\]
Correct Answer: C
Solution :
[c] The acid strength of oxyacids of the same halogen increases with increase in oxidation state of the halogen \[\overset{+7}{\mathop{HCl{{O}_{4}}}}\,>\overset{+5}{\mathop{HCl{{O}_{3}}}}\,>\overset{+3}{\mathop{HCl{{O}_{2}}}}\,>\overset{+1}{\mathop{HClO}}\,\] Thus Cl in \[HCl{{O}_{4}}\] is in highest oxidation state \[(+7)\] and hence strongest acid, while HC10 (Cl is in \[+1\] oxidation state) is weakest.
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