A) 1.0 mole of \[{{O}_{2}}\] at 560 K.
B) 0.50 mole of Ne at 500 K.
C) 0.20 mole of \[C{{O}_{2}}\] at 440 K.
D) 2.0 mole of He at 140 K.
Correct Answer: D
Solution :
[d] Average molecular speed \[=\sqrt{\frac{8RT}{\pi M}}\]is dependent on T and M. Thus, greater the value of \[\sqrt{\frac{T}{M},}\] greater the molecular speed. Thus, Gas \[\sqrt{\frac{T}{M}=\times 4}\] For \[{{O}_{2}}\sqrt{\frac{560}{32}}=4.18\] For \[Ne\sqrt{\frac{500}{20}}=5.0\] For \[{{O}_{2}}\sqrt{\frac{440}{44}}=3.16\] For \[He\sqrt{\frac{140}{4}}=5.91\]
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