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NEET Sample Paper NEET Sample Test Paper-86

  • question_answer
    A metal conductor of length 1 m rotates vertically about one of its ends at angular velocity 5 radians per second. If the horizontal component of earth's magnetic field is \[0.2\times {{10}^{-4}}T,\] then the e.m.f. developed between the two ends of the conductor is

    A) \[5\,\,mV\]        

    B)        \[50\,\,\mu V\]

    C) \[5\,\,\mu V\]                 

    D) \[50\,\,mV\]

    Correct Answer: B

    Solution :

    [b] \[\ell =1m,\]\[\omega =5rad\text{/}s,\]\[B=0.2\times {{10}^{-4}}T\] \[\varepsilon =\frac{B\omega \ell }{2}=\frac{0.2\times {{10}^{-4}}\times 5\times 1}{2}=50\mu V\]


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