A) increases
B) decreases
C) becomes zero
D) remains unchanged
Correct Answer: A
Solution :
[a] The electrostatic potential energy of the two electrons, placed at the seperation r from each other, is \[U=\left( \frac{1}{4\pi {{\varepsilon }_{0}}} \right)\frac{(-e)(-e)}{r}=\frac{{{e}^{2}}}{4\pi {{\varepsilon }_{0}}r}\] which increases when the one electron is brought towards the other and the separation r decreases.
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