A) \[\frac{1}{19}\]
B) 19
C) 1.5
D) 0.95
Correct Answer: B
Solution :
[b] \[\alpha =\frac{{{I}_{c}}}{{{I}_{e}}};\,\]\[\beta =\frac{{{I}_{c}}}{{{I}_{b}}}\] \[{{I}_{e}}={{I}_{b}}+{{I}_{c}},\]\[\frac{{{I}_{e}}}{{{I}_{c}}}=\frac{{{I}_{b}}}{{{I}_{c}}}+1\] \[\frac{1}{\alpha }=\frac{1}{\beta }+1,\]\[\frac{1}{0.95}=\frac{1}{\beta }+1\] \[\frac{1}{\beta }=\frac{1}{0.95}-1=\frac{0.05}{0.95}=\frac{5}{95}\] \[\beta =\frac{95}{5}=19.\]
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