NEET Sample Paper NEET Sample Test Paper-86

  • question_answer
    A spring of force constant 800 N/m has an extension of 5 cm. The work done in extending it from 5 cm to 15 cm is

    A) 16 J                 

    B)        8 J

    C) 32 J                 

    D)        24 J

    Correct Answer: B

    Solution :

    [b] Small amount of work done in extending the spring by dx is \[dW=k\text{ }x\text{ }dx\] \[\therefore \] \[W=k\int\limits_{0.05}^{0.15}{x\,\,dx}\] \[=\frac{800}{2}\left[ {{(0.15)}^{2}}-{{(0.05)}^{2}} \right]\] \[=400\,[(0.15+0.05)(0.15-0.05)]\] \[=400\times 0.2\times 0.1=8\,J\]


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