A) \[\sqrt{2gh}\]
B) \[\sqrt{4gh/3}\]
C) \[\sqrt{3/4gh}\]
D) \[\sqrt{4gh}\]
Correct Answer: B
Solution :
[b] By energy conservation \[{{(K.E)}_{i}}+{{(P.E)}_{i}}={{(K.E)}_{f}}+{{(P.E)}_{f}}\] \[{{(K.E)}_{i}}=0,{{(P.E)}_{i}}=mgh,{{(P.E)}_{f}}=0\] \[{{(K.E)}_{f}}=\frac{1}{2}I{{\omega }^{2}}+\frac{1}{2}mv_{cm}^{2}\] Where I (moment of inertia)\[=\frac{1}{2}m{{R}^{2}}\] (for solid cylinder) so mgh \[mgh={\scriptstyle{}^{1}/{}_{2}}({\scriptstyle{}^{1}/{}_{2}}m{{R}^{2}})\left( \frac{v_{cm}^{2}}{{{R}^{2}}} \right)+{\scriptstyle{}^{1}/{}_{2}}mv_{cm}^{2}\] \[\Rightarrow \]\[{{v}_{cm}}=\sqrt{4gh/3}\]
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