NEET Sample Paper NEET Sample Test Paper-86

  • question_answer
    The magnetic field of earth at the equator is approximately \[4\times {{10}^{-5}}\,T.\] The radius of earth is \[6.4\times {{10}^{6}}\,m.\] Then the dipole moment of the earth will be nearly of the order of:

    A) \[{{10}^{23}}\,\,\text{A}\,\,{{\text{m}}^{2}}\]          

    B)        \[{{10}^{20}}\,\,\text{A}\,\,{{\text{m}}^{2}}\]

    C) \[{{10}^{16}}\,\,\text{A}\,\,{{\text{m}}^{2}}\]          

    D)        \[{{10}^{10}}\,\,\text{A}\,\,{{\text{m}}^{2}}\]

    Correct Answer: A

    Solution :

    [a] Given, \[B=4\times {{10}^{-5}}T\] \[r=6.4\times {{10}^{6}}\,m\] Dipole moment of the earth M =? \[B=\frac{{{\mu }_{0}}}{4\pi }\frac{M}{{{r}^{3}}}\] \[4\times {{10}^{-5}}=\frac{4\pi \times {{10}^{-7}}\times M}{4\pi \times \left( 6.4\times {{10}^{6\,{{\,}^{3}}}} \right)}\]             \[M\cong {{10}^{23}}\,A{{m}^{2}}\]


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