NEET Sample Paper NEET Sample Test Paper-86

  • question_answer
    A particle moves such that its acceleration 'a' is given by a = -bx where x is the displacement from equilibrium position and b is constant. The period of oscillation is

    A) \[2\pi /b\]          

    B)        \[2\pi /\sqrt{b}\]

    C) \[\sqrt{2\pi /b}\] 

    D)        0\[2\sqrt{\pi /b}\]

    Correct Answer: B

    Solution :

    [b]  \[T=2\,\pi \sqrt{\frac{\text{displacement}}{\text{acceleration}}}\] \[=2\pi \sqrt{\frac{x}{bx}}=2\pi /\sqrt{b}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner