A) \[9\times {{10}^{19}}\,J\]
B) \[9\times {{10}^{17}}\,J\]
C) \[9\times {{10}^{16}}\,J\]
D) \[9\times {{10}^{13}}\,J\]
Correct Answer: D
Solution :
[d] \[0.1%\,\,of\,\,1\,\,kg=0.001\,\,kg\] From the formula, \[E=m{{c}^{2}}\] Energy released \[=0.001\times {{(3\times {{10}^{8}})}^{2}}\,\,joules\] \[=9\times {{10}^{16}}\times {{10}^{-3}}=9\times {{10}^{13}}\,\,J\]
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