A) \[{{\text{ }\!\![\!\!\text{ SiC}{{\text{l}}_{\text{6}}}\text{ }\!\!]\!\!\text{ }}^{2-}}\]
B) \[{{[Ge{{F}_{6}}]}^{2-}}\]
C) \[{{[CC{{l}_{6}}]}^{2-}}\]
D) \[{{[SnC{{l}_{6}}]}^{2-}}\]
Correct Answer: C
Solution :
[c] Carbon cannot expand its coordination number beyond four due to the absence of d-orbitals, hence it cannot form \[{{[CC{{l}_{6}}]}^{2-}}\] ion.
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