A) \[N{{O}_{2}}\] can be prepared by heating \[Pb{{(N{{O}_{3}})}_{2}}\]
B) \[N{{O}_{2}}\] is red - brown gas
C) \[N{{O}_{2}}\] is diamagnetic
D) \[N{{O}_{2}}\] readily dimerises to \[{{N}_{2}}{{O}_{4}}\]
Correct Answer: C
Solution :
[c] \[N{{O}_{2}}\] is paramagnetic and readily dime rises to \[{{N}_{2}}{{O}_{4}}\] which is diamagnetic.
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