A) 356.2
B) 456.8
C) 530.1
D) 656.7
Correct Answer: A
Solution :
[a] Given vapour pressure of pure solute \[({{P}^{0}})=121.8\,\,MM;\] Weight of solute\[(w)=15\,\,g\] Weight of solvent \[(W)=250\,g;\] Vapour pressure of pure solvent \[(P)=120.2\,\,mm\] and Molecular weight of solvent \[(M)=78\] From Raoult's law \[=\frac{{{P}^{o}}-P}{{{P}^{O}}}=\frac{w}{m}\times \frac{M}{W}=\frac{121.8-120.2}{121.8}=\frac{15}{m}\times \frac{78}{250}\] or \[m=\frac{15\times 78}{250}\times \frac{121.8}{1.6}=356.2\]
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