A) Cyanamide ion \[(C{{N}_{2}}^{2-})\] is isoelectronic with\[C{{O}_{2}}\] and has the same linear structure
B) \[M{{g}_{2}}{{C}_{3}}\] reacts with water to form propyne
C) \[Ca{{C}_{2}}\] has NaCl type lattice
D) All of the above
Correct Answer: D
Solution :
[d] In \[C{{O}_{2}}\], we have \[22\,\,(6+8+8=22)\] electrons. In \[(C{{N}_{2}}^{2-}),\] we have \[22\,(6+7+7+2=22)\] electrons. Both\[C{{O}_{2}}\] and \[(C{{N}_{2}}^{2-})\] have linear structures. Thus, statement [a] is correct. \[M{{g}_{2}}{{C}_{3}}+4{{H}_{2}}O\xrightarrow{{}}\] \[2Mg{{(OH)}_{2}}+\underset{Propyne}{\mathop{C{{H}_{3}}C\equiv CH}}\,\] i.e., statement [b] is also correct. The structure of \[Ca{{C}_{2}}\] is of \[NaCl\]type i.e., statement [c] is also correct.
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