A) \[C{{H}_{2}}=CCl\,-CH=C{{H}_{2}}\]
B) \[CC{{l}_{2}}\,=\,CC{{l}_{2}}\]
C) \[C{{H}_{2}}=C=C{{H}_{2}}\]
D) \[C{{H}_{2}}=CH-CH=C{{H}_{2}}\]
Correct Answer: C
Solution :
[c] \[\overset{S{{P}^{2}}}{\mathop{C{{H}_{2}}}}\,=\overset{SP}{\mathop{C}}\,=\overset{S{{P}^{2}}}{\mathop{C{{H}_{2}}}}\,\]
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