A) \[IC{{H}_{2}}OCH{{(C{{H}_{3}})}_{2}}\]
B) \[\begin{align} & C{{H}_{3}}OC{{(C{{H}_{3}})}_{2}} \\ & | \\ & I \\ \end{align}\]
C) \[C{{H}_{3}}I+{{(C{{H}_{3}})}_{2}}CHOH\]
D) \[C{{H}_{3}}OH+{{(C{{H}_{3}})}_{2}}CHI\]
Correct Answer: C
Solution :
[c] In case ofunsymmetrical ethers, the site of cleavage depends on the nature of alkyl group e.g., \[C{{H}_{3}}O-CH{{(C{{H}_{3}})}_{2}}+HI\xrightarrow{373K}\] \[\underset{Methyl\,\,iodide}{\mathop{C{{H}_{3}}I+}}\,\underset{Isopropyl\,\,alcohol}{\mathop{{{(C{{H}_{3}})}_{2}}CHOH}}\,\] The alkyl halide is always formed from the smaller alkyl group.
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