question_answer

What is Z in the following sequence of reactions? \[Z\xrightarrow{PC{{I}_{5}}}X\xrightarrow{ALC.KOH}Y\xrightarrow[(ii){{H}_{2}}O;\,boil]{(i)\,Conc.\,{{H}_{2}}S{{O}_{4}}}Z\]

A) \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}OH\]      

B) \[C{{H}_{3}}CH(OH)C{{H}_{3}}\]

C) \[{{(C{{H}_{3}}C{{H}_{2}})}_{2}}CHOH\]    

D) \[C{{H}_{3}}CH=C{{H}_{2}}\]

Correct Answer: B

Solution :

[b] Reagents used in the various steps indicate that the compound Z has an alcoholic group. This set of reactions is possible only when Z is \[C{{H}_{3}}CHOHC{{H}_{3}}\]. In options a and c, Y cannot be converted back into d by the given series of reactions.