A) 1603
B) 1896
C) 2230.59
D) 2730
Correct Answer: C
Solution :
[c] \[{{v}_{oxg.}}=\sqrt{\frac{3R\times 289}{32}}\] \[\left( {{v}_{rms}}=\sqrt{\frac{3RT}{M}} \right)\] \[{{v}_{H}}=\sqrt{\frac{3R\times 400}{2}}\]so \[{{v}_{H}}=2230.59\,m/\sec \]
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