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NEET Sample Paper NEET Sample Test Paper-84

  • question_answer
    During an adiabatic compression, 830 J of work is done on 2 moles of a diatomic ideal gas to reduce its volume by 50%. The change in its temperature is nearly:\[(R=8.3\,\,J{{K}^{-1}}mo{{l}^{-1}})\]

    A) 40 K                 

    B)        33 K

    C) 20 K     

    D) 14 K

    Correct Answer: C

    Solution :

    [c] Given: Work done, W= 830 J No. of moles of gas, \[\mu =2\] For diatomic gas \[\gamma =1.4\] Work done during an adiabatic change             \[W=\frac{\mu R({{T}_{1}}-{{T}_{2}})}{\gamma -1}\] \[\Rightarrow \] \[830=\frac{2\times 8.3(\Delta T)}{1.4-1}=\frac{2\times 8.3(\Delta T)}{0.4}\] \[\Rightarrow \] \[\Delta T=\frac{830\times 0.4}{2\times 8.3}=20K\]           


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