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NEET Sample Paper NEET Sample Test Paper-84

  • question_answer
    The path difference between the two waves : \[{{y}_{1}}={{a}_{1}}\sin \left( \omega t-\frac{2\pi x}{\lambda } \right)\]and\[{{y}_{2}}={{a}_{2}}\sin \left( \omega t-\frac{2\pi x}{\lambda }+\phi  \right)\]will be

    A) \[\frac{2\pi }{\lambda }\phi \]     

    B)        \[\frac{2\pi }{\lambda }\left( \phi -\frac{\pi }{2} \right)\]

    C)  \[\frac{\lambda }{2\pi }\phi \]

    D)        \[\frac{2\pi }{\lambda }\left( \phi +\frac{\pi }{2} \right)\]

    Correct Answer: C

    Solution :

    [c] Phase difference \[=\phi \]      Path diff\[=\frac{\lambda }{2\pi }\times \]phase diff. \[=\frac{\lambda }{2\pi }\phi \]      


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