A) \[3\,\,m{{s}^{-1}}\]
B) \[2.5\,\,m{{s}^{-1}}\]
C) \[2\,\,m{{s}^{-1}}\]
D) \[1\,\,\,m{{s}^{-1}}\]
Correct Answer: D
Solution :
[d] Let u be the initial velocity that have to find and a be the uniform acceleration of the particle. For t = 3 s, distance travelled S = 12 m and for t = 3 + 3 = 6s distance travelled S'=12 + 30 = 42 m From, \[S=ut+1/2a{{t}^{2}}\] \[12=u\times 3+\frac{1}{2}\times a\times {{3}^{2}}\] or \[\,24=6u+9a\,\] ?(i) Similarly, \[42=u\times 6+\frac{1}{2}\times a\times {{6}^{2}}\] or \[42=6u+18a\] ?(ii) On solving, we get \[u=1\,\,m\,{{s}^{-1}}\]
You need to login to perform this action.
You will be redirected in
3 sec
