question_answer

Plates of area A are arranged as shown. The distance between each plate is d, the net capacitance is

A) \[\frac{{{\varepsilon }_{0}}A}{d}\]        

B)                    \[\frac{7{{\varepsilon }_{0}}A}{d}\]

C)        \[\frac{6{{\varepsilon }_{0}}A}{d}\]

D)                    \[\frac{5{{\varepsilon }_{0}}A}{d}\]

Correct Answer: A

Solution :

[a] The equivalent circuit is shown in figure Thus, \[{{C}_{ab}}=C=\frac{{{\varepsilon }_{0}}A}{d}\]