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NEET Sample Paper NEET Sample Test Paper-84

  • question_answer
    The dimensions of \[a\times b\] in the relation \[E=\frac{b-{{x}^{2}}}{at}\] where E is the energy, x is the displacement and t is time are

    A) \[M{{L}^{2}}T\]         

    B)        \[{{M}^{-1}}{{L}^{2}}T\]

    C) \[M{{L}^{2}}{{T}^{-2}}\]                             

    D)        \[ML{{T}^{-2}}\]

    Correct Answer: B

    Solution :

    [b] Here, b and \[{{x}^{2}}={{L}^{2}}\] have same dimensions Also, \[a=\frac{{{x}^{2}}}{E\times t}=\frac{{{L}^{2}}}{(M\,\,{{L}^{2}}{{T}^{-2}}\,\,T\,\,\,}={{M}^{-1}}{{T}^{1}}\]               \[a\times b=[{{M}^{-1}}{{L}^{2}}T]\]


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