NEET Sample Paper NEET Sample Test Paper-83

  • question_answer
    A 200 V input is supplied to a transformer. The output circuit draws a current of 2.0 A at 440 V. If efficiency of transformer is \[80\,%\], the current drawn by the primary winding of the transformer is

    A)  3.6 A              

    B)  2.8 A

    C)  2.5 A              

    D)  5.0 A

    Correct Answer: D

    Solution :

    Given, \[\left( Input voltage \right){{V}_{p}} =220 V\] \[\left( Output voltage \right){{V}_{s}} =440 V\] \[\left( Input current \right){{I}_{p}} = ?\] \[\left( Output current \right) {{l}_{s}} = 2 A\] Efficiency of the transformer, \[\eta  = 80\,%\] Efficiency of the transformer is given by \[\eta  = \frac{output\,\,power}{input\,\,power}=\frac{{{V}_{s}}{{l}_{s}}}{{{V}_{p}}{{l}_{p}}}\]\[or\,\,\,\,\,{{l}_{p}}=\frac{{{V}_{s}}{{l}_{s}}}{\eta {{V}_{p}}}=\frac{(440)(2)}{\left( \frac{80}{100} \right)(220)}=5\,A\]


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