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NEET Sample Paper NEET Sample Test Paper-83

  • question_answer
    Value of equilibrium constant for following reaction is 0.50 at\[400{}^\circ C\]. What is the value of \[{{K}_{p}}\] at\[400{}^\circ C\]. When the unit of pressure is in atmosphere and unit of concentration is in\[m{{L}^{-1}}\]. Chemical reaction is \[{{N}_{2}}(g)+3{{H}_{2}}(g)\,\,\,\,2N{{H}_{3}}(g)\]

    A)  \[1.64\,\times \,\,1{{0}^{-}}^{3}\]                  

    B)  \[1.64\times 1{{0}^{4}}\]

    C)  \[1.64\times 1{{0}^{-\,4}}\]                 

    D)  \[164\times 1{{0}^{-\,4}}\]

    Correct Answer: C

    Solution :

    We know that \[{{\operatorname{K}}_{p}}={{K}_{C}}{{(RT)}^{\Delta }}^{n}\] \[= \,0.50{{\left( RT \right)}^{-}}^{2},\,= \,0.50 {{\left( 0.082\,\,\times \,\,673 \right)}^{-}}^{2}\] \[=\,\,\,1.64 \times 1{{0}^{-}}^{4}\]


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