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NEET Sample Paper NEET Sample Test Paper-83

  • question_answer
    Arrange the given complex ions in ascending order of increasing crystal field splitting energy\[({{\Delta }_{0}})\]. [a] \[{{\left[ Cr{{\left( Cl \right)}_{6}} \right]}^{\,3\,-}}\] [b] \[{{\left[ (Cr{{\left( CN \right)}_{6}} \right]}^{\,3\,-}}\]             [c] \[{{\left[ Cr{{\left( N{{H}_{3}} \right)}_{6}} \right]}^{\,3\,+}}\]

    A)  \[\operatorname{A}<B<C\]                  

    B)  \[A<C<B\]

    C)  \[\operatorname{B}<C<A\]                  

    D)  \[\operatorname{C}<B<A\]

    Correct Answer: B

    Solution :

    CFSE is higher when the complex contains strong field ligand. Thus, crystal field splitting energy increases in the order \[{{[CrC{{l}_{6}}]}^{3\,-}}\,<\,\,{{[Cr{{(N{{H}_{3}})}_{6}}]}^{3\,+}}\,<\,\,{{[Cr{{(CN)}_{6}}]}^{3\,-}}\] Because the order of field strength is\[\operatorname{C}{{l}^{-}}\,N{{H}_{3}}<C{{N}^{-}}\]


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