A) \[{{H}_{2}}{{S}_{4}}{{O}_{8}} + {{H}_{2}}O\]
B) \[\operatorname{BaO} + HCl\]
C) \[\operatorname{Mg}\,\,+\,\,{{H}_{2}}O\]
D) \[{{\operatorname{Na}}_{2}}{{O}_{2}}+\,\,2HCl\]
Correct Answer: C
Solution :
Only [c] will produce Hg as follows\[\operatorname{Mg}\,+\,\,{{H}_{2}}O\,\,\xrightarrow{{}}\,\,Mg{{(OH)}_{2}}+{{H}_{2}}\uparrow \]
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