A) \[{{\operatorname{H}}_{2}}O, \,{{H}_{2}}S{{O}_{4}}\]
B) \[{{O}_{2}}\]
C) \[Cr{{O}_{3}},\,\,{{H}_{2}}S{{O}_{4}}\]
D) m C P B A
Correct Answer: D
Solution :
mCPBA is meta chloroperbenzoic acid can be used to lead above conversion.
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