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NEET Sample Paper NEET Sample Test Paper-83

  • question_answer
    A non-conducting infinitely long plane sheet has given a charge in such a way that \[{{Q}_{1}}\] appears on one side and \[{{Q}_{2}}\] appears on other side. The face area of plate is A, then electric at points 1 and 2 is

    A)  \[\frac{{{Q}_{1}}-{{Q}_{2}}}{2\,{{\varepsilon }_{0}}A},\,\,\frac{{{Q}_{1}}-{{Q}_{2}}}{2\,{{\varepsilon }_{0}}A}\]           

    B)  \[\frac{{{Q}_{1}}+{{Q}_{2}}}{2\,{{\varepsilon }_{0}}A},\,\,\frac{{{Q}_{1}}+{{Q}_{2}}}{2\,{{\varepsilon }_{0}}A}\]

    C)  \[\frac{{{Q}_{1}}+{{Q}_{2}}}{2\,{{\varepsilon }_{0}}A},\,\,\frac{{{Q}_{1}}-{{Q}_{2}}}{2\,{{\varepsilon }_{0}}A}\]       

    D)  \[\frac{{{Q}_{1}}+{{Q}_{2}}}{{{\varepsilon }_{0}}A},\,\,\frac{{{Q}_{1}}-{{Q}_{2}}}{{{\varepsilon }_{0}}A}\]  

    Correct Answer: C

    Solution :

    At 1, \[{{\operatorname{E}}_{1}} = \frac{{{\sigma }_{2}}}{2{{\varepsilon }_{0}}}+\frac{{{\sigma }_{1}}}{2{{\varepsilon }_{0}}} towards left\] At 2, \[{{\operatorname{E}}_{2}} = \frac{{{\sigma }_{2}}}{2{{\varepsilon }_{0}}}+\frac{{{\sigma }_{1}}}{2{{\varepsilon }_{0}}} towards right\] \[{{\sigma }_{2}}=\frac{{{Q}_{2}}}{A}\,and\,\,{{\sigma }_{1}}=\frac{{{Q}_{1}}}{A}\] \[\therefore \,\,\,\,\,\,\,\,\,{{E}_{1}}=\frac{{{Q}_{1}}+{{Q}_{2}}}{2\,{{\varepsilon }_{0}}A}\] and \[{{E}_{2}}=\frac{{{Q}_{2}}-{{Q}_{1}}}{2\,{{\varepsilon }_{0}}A}\]


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