A) \[20\times {{\left( 2 \right)}^{1/3}}\,cm\]
B) \[20\times {{\left( 2 \right)}^{2/3}}\,cm\]
C) 20 cm
D) \[20\times \left( 2 \right)\,\,cm\]
Correct Answer: A
Solution :
For no deflection in tan A position \[\frac{{{\mu }_{0}}2{{M}_{1}}}{4\pi d_{1}^{3}}=\frac{{{\mu }_{0}}}{4\pi }\frac{2{{M}_{2}}}{d_{2}^{3}}\] \[\frac{{{M}_{1}}}{{{M}_{2}}}={{\left( \frac{{{d}_{1}}}{{{d}_{2}}} \right)}^{3}}\] \[\left( \frac{1}{2} \right)={{\left( \frac{20}{{{d}_{2}}} \right)}^{3}}\] \[{{d}_{2}}=\,20\times {{\left( 2 \right)}^{1/3}}\,cm\]
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