A) 12 N
B) 5 N
C) 7.2 N
D) 13 N
Correct Answer: D
Solution :
\[\operatorname{Force} applied = 12 N\] \[\therefore \,\,\,\,\,\,\,\,\,\,{{f}_{\max }}\,\,=\,\mu R\times \,0.6\times 12\,N\,\,=\,\,7.2\,\,N\] This shows that \[{{f}_{\max }}\,>W\] The net contact force is given by \[F=\sqrt{{{R}^{2}}+{{f}^{2}}}=\sqrt{{{12}^{2}}+{{5}^{2}}}\] \[=\,\,\sqrt{144+25}\] \[\operatorname{F}=13\,\,N\]
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