A) \[\frac{3}{2}\]
B) \[\frac{4}{3}\]
C) \[\frac{9}{8}\]
D) \[\frac{5}{3}\]
Correct Answer: A
Solution :
Power of lens P (in dioptre) \[=\,\,\,\frac{100}{focal\,length\,f(in\,cm)}\] \[\therefore f=\frac{100}{10}=10\,\,cm\] According to lens maker?s formula \[\frac{1}{f}=(\mu -1)\left( \frac{1}{{{R}_{1}}}-\frac{1}{{{R}_{2}}} \right)\] For biconvex lens, \[{{\operatorname{R}}_{1}}=\,\,+R,\,\,{{R}_{2}}=-R\] \[\therefore \,\,\,\,\,\,\,\,\frac{1}{f}=(\mu -1)\left( \frac{1}{R}+\frac{1}{R} \right)\] \[\frac{1}{f}=(\mu -1)\left( \frac{2}{R} \right)\] \[\frac{1}{10}=(\mu -1)\left( \frac{2}{10} \right)\] \[(\mu -1)=\frac{1}{2}\,\,or\,\,\,\frac{3}{2}\]
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