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NEET Sample Paper NEET Sample Test Paper-82

  • question_answer
    Molarity is the number of moles of solute present in one litre of the solution obtained by mixing 150 mL 0.48 M \[{{H}_{2}}S{{O}_{4}}\] with 0.26 M\[{{H}_{2}}S{{O}_{4}}\]. What is the molarity of the resultant solution?

    A)  4.25 M                        

    B)  0.425 M

    C)  42.5 M                        

    D)  0.74 M

    Correct Answer: B

    Solution :

    Given, \[{{\operatorname{M}}_{1}} = 0.26 M, {{M}_{2}} = 0.48 M\] \[{{\operatorname{V}}_{1}}=50mL,\,{{V}_{2}}=\,\,150\,mL\] Let \[{{\operatorname{M}}_{3}}\,\,=\,\,molarity\,\,of\,\,resultant\,\,solution\] \[{{V}_{3}}=150+50\] \[= \,\,200 mL\] Applying mixing formula \[{{M}_{1}}{{V}_{1}}+{{M}_{2}}{{V}_{2}}={{M}_{3}}{{V}_{3}}\] \[{{M}_{3}}=\frac{{{M}_{1}}{{V}_{1}}+{{M}_{2}}{{V}_{2}}}{{{V}_{3}}}\] \[=\,\,\,\frac{0.26\times 50+0.48\times 150}{200}\] \[= \,0.425 M\]


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