question_answer

Calculated magnetic momentum of \[E{{u}^{3\,+}}\] is

A)  0                                

B)  7.94

C)  2.83                            

D)  3.87

Correct Answer: A

Solution :

Electronic configuration of \[E{{u}^{3\,+}}\] is \[\left[ Xe \right]\,4{{f}^{7}}5{{d}^{0}} 6{{s}^{0}}\] \[l=0\] \[{{\mu }_{cal}}\,\,=\,\,\sqrt{4s\left( s+1 \right)+L\left( L+1 \right)}\] \[\therefore \,\,\,\,\,\,\,\,\,\,\,{{\mu }_{cal}}\,\,=\,\,0\]