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NEET Sample Paper NEET Sample Test Paper-82

  • question_answer
    The dip at a place in \[\delta \]. For measuring it, the axis of the dip needle is perpendicular to the magnetic meridian if the axis of the dip needle makes an angle \[\theta \] with the magnetic meridian, the apparent dip will be

    A)  \[\tan \,\delta  cosec\,\theta \]     

    B)  \[\tan \,\delta  \sin \,\theta \]

    C)  \[\tan \,\delta  \cos \,\theta \]                  

    D)  \[\tan \,\delta  \sec \,\theta \]

    Correct Answer: A

    Solution :

    \[\tan \delta =\frac{V}{H}\] \[\tan {{\delta }_{1}}=\frac{V}{H\,\cos (90-\theta )}\] \[=\frac{\tan \delta }{\cos (90-\theta )}\,\,\,=\,\,\tan \delta \,\cos ec\,\theta \]


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