A) \[02\,\,kg-m{{s}^{-}}^{1}\]
B) \[-\,02\,\,kg-m{{s}^{-}}^{1}\]
C) \[0.1\,\,kg-m{{s}^{-}}^{1}\]
D) \[-\,0.4\,\,kg-m{{s}^{-}}^{1}\]
Correct Answer: A
Solution :
The impulse is given by \[l=change in momentum\] \[=\,\,\Delta p=m\Delta v=m\frac{\Delta x}{\,\Delta t}\] Given, \[\operatorname{m} =\,\,0.1 kg; \frac{\Delta x}{\Delta t} = \frac{4}{2} m{{s}^{-}}^{1}= 2 m{{s}^{-}}^{1}\] \[\therefore \,\,\,\,\,\,\,\,\,\,l=0.1\times 2=0.2kg-m{{s}^{-}}^{1}\]
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