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NEET Sample Paper NEET Sample Test Paper-7

  • question_answer
    A piece of wood from an archaeological source shows a \[^{14}C\] activity which is 60% of the acitivity found in a fresh wood today. Calculate the age of the archaeological sample. Half-life period of C-14 is 5770 year

    A)  3215 year                  

    B)  6216 year

    C)  4258 year                  

    D)  2129 year

    Correct Answer: C

    Solution :

    \[K=\frac{0.693}{{{t}_{{\scriptstyle{}^{1}/{}_{2}}}}}=\frac{0.693}{5770}=1.2\times {{10}^{-4}}yea{{r}^{-1}}\] \[{{N}_{0}}=100,\]  \[{{N}_{N=60}}=100,\]                 \[t=\frac{2.303}{K}\log \frac{{{N}_{0}}}{N}\]                 \[=\frac{2.303}{1.2\times {{10}^{-4}}}\log \frac{100}{60}=4258year\]


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