2. Sample Papers
  3. NEET

NEET Sample Paper NEET Sample Test Paper-79

  • question_answer
    A certain piece of wood contains 6 g of \[\operatorname{C} -14\] whose half-life is 2400 years. After 7200 years, the amount of \[\operatorname{C} -14\] left in that piece of wood will be

    A)  3 g                              

    B)  1.5 g                

    C)  0.75 g             

    D)  None of these

    Correct Answer: C

    Solution :

    Number of half-lives \[n=\frac{7200}{2400}\,\,=\,\,3\] \[\therefore \,\,\,Amount\,\,of\,\,C-14\,\,left\,\,=\,\frac{6g}{{{(2)}^{n}}}=\frac{6}{{{2}^{3}}}\] \[=\,\,\frac{6}{8}=0.75\,g\]


You need to login to perform this action.
You will be redirected in 3 sec spinner